 
Page 1 of 5
Q1)
In the table provided below, the results of a new diagnostic test for Cancer are
compared  with  the  complete  diagnostic  package  in  current  use  in  a  random 
sample  representing  the  general  population.  What  are  the  sensitivity, 
specificity, accuracy, PPV and NPV of the new test. Would you recommend it 
for screening purposes in the general population? Would you justify its use for 
diagnosis of Cancer? For what purpose such test is good for? 
Q2)
A physical examination was used to screen for breast Cancer in 2500 women
with  biopsy  proven  adenocarcinoma  of  the  breast  and  in  5000  age  and  race 
matched control women. The results of the physical examination were positive 
(i.e. a mass was palpated) in 1800 cases and 800 control women (who showed 
no evidence of cancer at biopsy). 
Q3)
A colon Cancer screening study is being conducted in a town. Individuals
aged 50 to 75 years will be screened with the hemoccult test, a stool sample is 
tested for the presence of blood (RBCs under microscope). The hemoccult test 
has a sensitivity of 70% and a specificity of 75%. If the prevalence of ca colon 
in  the  population  of  50-75  years  of  age  in  this  town  is  20/1000,  What  is  the 
PPV  for  this  test?  Interpret  the  value  of  PPV.  Use  a  hypothetical  sample  of 
5000. 
 
Page 2 of 5
Q1)
In the table provided below, the results of a new diagnostic test for Cancer are
compared  with  the  complete  diagnostic  package  in  current  use  in  a  random 
sample  representing  the  general  population.  What  are  the  sensitivity, 
specificity, accuracy, PPV and NPV of the new test. Would you recommend it 
for screening purposes in the general population? Would you justify its use for 
diagnosis of Cancer? For what purpose such test is good for? 
Complete diagnosis (true disease status)
New test
Ca Present
Ca absent
Total
+ve
9
1000
1009
-ve
1
9000
9001
Total
10
10000
10010
Sensitivity =
(9/10)x100
=90%
Specificity =
(9000/10000)x100 =90%
Prevalence (pretest probability)=  (10/10010)x100000  =99.9/100,000 
PPV = 
(9/1009)x100
=0.9%
NPV =
(9000/9001)x100
=99.99%
I would not recommend it for screening purposes although the test is fairly
sensitive  (90%)  because  the  prevalence  of  the  diseases  in  general  population  is  very 
low (99.9 per 100000) resulting in very low PPV (1% only), therefore only 1 in every 
100  possible  case  is  really  Ca  resulting  in  unnecessary  anxiety  on  the  part  of  false 
positive Ca cases. 
 
I  would  not  justify  its  use  for  establishing  the  diagnosis  of  Ca  since  its  PPV  is 
very low (1% only)
 
The  test  is  suitable  to  exclude  a  possible  diagnosis  of  Ca  in  subjects  with  no 
other  reason  to  suspect  a  Ca  in  them  (like  in  screening)  since  its  NPV  is  almost 
perfect (100%). 
 
Page 3 of 5
Q2)
A physical examination was used to screen for breast Cancer in 2500 women
with  biopsy  proven  adenocarcinoma  of  the  breast  and  in  5000  age  and  race 
matched control women. The results of the physical examination were positive 
(i.e. a mass was palpated) in 1800 cases and 800 control women (who showed 
no evidence of cancer at biopsy). 
biopsy proven adenocarcinoma of the breast
Physical examination
Ca Present
Ca absent
Total
+ve
-ve
Total
2500
5000
7500
What are the sensitivity, specificity, proportion of false positive and false
negative test, accuracy, PPV and NPV of  physical examination when  used to predict 
Ca breast? What is the pretest probability of breast Ca in the present example? 
 
 
biopsy proven adenocarcinoma of the breast
Physical examination
Ca Present
Ca absent
Total
+ve
1800
800
2600
-ve
700
4200
4900
Total
2500
5000
7500
Sensitivity =
(1800/2500)x100
=72%
Specificity =
(4200/5000)x100
=84%
Prevalence (pretest probability)= (2500/7500)x100
=33.3%
PPV =
(1800/2600)x100
=69.2%
NPV =
(700/4900)x100
=85.71%
Proportion of false positive=
100-specificity = 100-84 =16%
Proportion of false negative=
100-sensitivity = 100-72 =28%
 
 
 
 
Page 4 of 5
Q3)
A colon Cancer screening study is being conducted in a town. Individuals
aged 50 to 75 years will be screened with the hemoccult test, a stool sample is 
tested for the presence of blood (RBCs under microscope). The hemoccult test 
has a sensitivity of 70% and a specificity of 75%. If the prevalence of ca colon 
in  the  population  of  50-75  years  of  age  in  this  town  is  2/1000,  What  is  the 
PPV  for  this  test?  Interpret  the  value  of  PPV.  Use  a  hypothetical  sample  of 
5000. 
 
Prevalence = Total diseased / Total sample examined = 2/1000 = 0.002 
Sensitivity = T+/total diseased = 0.70 
Specificity = T- / total disease free = 0.75. 
 
0.002 = Total diseased / 5000 
Total diseased = 5000 x 0.002 = 10 
 
0.70 = T+/10 
T+ = 0.70x10=7 
 
0.75 = T- / (5000-10) 
T- = 0.75 x 4990 = 3743 
 
Final diagnosis of Ca colon
hemoccult test
Ca Present
Ca absent
Total
+ve
T+
F+
-ve
F-
T-
Total
Total diseased
Total disease free
5000
 
 
Final diagnosis of Ca colon
hemoccult test
Ca Present
Ca absent
Total
+ve
7
1247
1254
-ve
3
3743
3746
Total
10
4990
5000
PPV = (7/1254)x100 =0.6%
 
The  PPV  is  very  low.  The  test  is  of  no  use  in  establishing  the  diagnosis  of  Ca 
colon, since the confidence in its positive value is less than 1%.
 
Page 5 of 5
Formula used in calculations
Disease status
Test results
Disease 
positive 
Disease
free
Total
+ve
(A)
True +ve test
(B)
False +ve test
Total positive test
results
-ve
(C)
False –ve test
(D)
True -ve test
Total negative
test results
Total
Total cases
(disease)
Total non-cases
(disease free)
Total sample
 
Sensitivity 
=  
Number of true positives
=
A
Number of diseased people
A+C
Proportion of false negative = 1-sensitivity or 100-sensitivity%
Specificity 
=  
Number of true negative
=
D
Number of disease free people
B+D
Proportion of false positive = 1-specificity or 100-specificity%
Accuracy =
Number of true +ve and -ve
=
A+D
Total sample size
A+B+C+D
PPV =
Number of true positive
=
A
Number of all positive test results
A+B
NPV =
Number of true negative
=
D
Number of all negative test results
C+D
